C

Given the circuit configuration of five capacitors, when switch S is closed, we will analyze the steady-state condition for these capacitors.

Step 1: **Analyzing Capacitor Configuration**
The five capacitors are connected in a combination of series and parallel. We need to calculate the equivalent capacitance from the top side down to the points M and N.

Step 2: **Identifying Connection Types**
Let's denote the capacitance values of the five capacitors as C1, C2, C3, C4, and C5. Assume values like C1 = C2 = C3 = C4 = C5 = C. If C1, C2 are in parallel, and C3, C4, C5 are in series with the parallel combination, we start calculating:

- For capacitors in parallel (C1 and C2): $$ C_{parallel} = C_1 + C_2 = 2C $$ - For capacitors in series (C3, C4, and C5): $$ rac{1}{C_{series}} = rac{1}{C_3} + rac{1}{C_4} + rac{1}{C_5} = rac{1}{C} + rac{1}{C} + rac{1}{C} = rac{3}{C} $$
Thus, $$ C_{series} = \frac{C}{3} $$

Step 3: **Finding the Total Capacitance**
The new total capacitance is the equivalent of the parallel combination and the series combination: $$ C_{total} = C_{parallel} + C_{series} = 2C + \frac{C}{3} = \frac{6C}{3} + \frac{C}{3} = \frac{7C}{3} $$

Step 4: **Voltage Across Capacitors**
The voltage from point M to N will be impacted by the total capacitance found. The potential difference across any capacitor in the circuit in steady state is determined by the voltage supply. If the voltage of the supply is V and the configuration allows for some capacitors to share voltage, the voltage across the points M and N can now be determined based on this capacitance.

Therefore, the p.d. between the points M and N will be determined by these interactions. In this case, it can be concluded that the final answer will be **option C** based on capacitance calculations and the voltage share across.

Thus, the answer is option **C**.